Cyclopropane combusts according to the following reaction: 2 C3H6(g) + 9 Ozlg) 9 6 C02lg) + 6 H20(g;AH= -3918.4 kl 14. Calculate the molar enthalpy…

these questions are connected, did i do both of them correcrly? please explain

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Cyclopropane combusts according to the following reaction: 2 C3H6(g) + 9 Ozlg) 9 6 C02lg) + 6 H20(g;AH= -3918.4 kl 14. Calculate the molar enthalpy of combustion for cyclopropane. m4 :—‘5‘11$,L43