Phenol (C6H5OH) has a pKa of 9. Calculate the percent ionized in 0.0794 M phenol–a dilute solution.

Phenol (C6H5OH) has a pKa of 9.89. Calculate the percent ionized in 0.0794 M phenol–a dilute solution.

Phenol (C6H5OH) has a pKa of 9.89. Calculate the percent ionized in 0.0794 M phenol–a dilutesolution.C6H5OH -> C6H5O-+H+Let x M took part in reactionpKa = -log10[Ka] = 9.89Ka =…

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